In cell B5T5, a Banker holding two-card total 5 (2+3) faces a Player fifth card valued at 5 (5). Under BANKER_TABLEAU[5][5], the Banker DRAWS, resolving in 6 cards with a 19B / 35P / 6T split across the 60 (P0..P5 × 6th-card 0..9) branches.
Verified scoreboard paired with tableau cell B5T5 (Banker 5 vs Player 3rd card 5).
Column 2 has 3 beads. Column 1 has 2 beads. Different depth → blue (≠).
Common table reading watchout: Comparing the wrong columns. Compare Column 2, the one that just finished, with Column 1.
This bead is at Row 4. Column 1 stopped at Row 2, more than one row above → red (=).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 1 stopped exactly one row above this bead.
Column 6 has 1 bead. Column 3 has 4 beads. Different depth → blue (≠).
Common table reading watchout: Comparing the wrong columns. Compare Column 6, the one that just finished, with Column 3.
Verified via bankerShouldDraw(5, 5) === true on pair 2+3.
Exact resolution across 6 legal Player starts (0–5) × 10 sixth-card values (0–9).
Three-card Player totals produced when fifth card 5 (5) lands on P0..P5.
How standing Banker 5 fares against the 6 Player 3-card totals for P3=5.
Sample sixth card 9 (9) verified through resolveHand().
Under [B5T5], Banker holds two-card total 5 (2+3) while Player draws fifth-card 5 (point value 5) onto an initial 0–5 total. Across those six legal Player starts, [B5T5] produces three-card Player totals of P0+5->5, P1+5->6, P2+5->7, P3+5->8, P4+5->9, P5+5->0.
Because [B5T5] sits inside the active draw window for Banker 5, the dealer deals a sixth card to 2+3: across all 60 (P0..P5 × sixth-card 0..9) combinations in [B5T5], Banker captures 19 wins, Player captures 35 wins, and 6 branches tie.
| B5T5 Player Start | B5T5 5th Card | B5T5 Banker 5 Action | B5T5 10-Card Split | B5T5 Sample Result |
|---|---|---|---|---|
| [B5T5:P0] 6+4=0 | [B5T5:5th] +5(5) -> P=5 | [B5T5:6th] B=5 draws (+9->4) | [B5T5:Split] 4B/5P/1T | [B5T5:Cards] 6c (P) |
| [B5T5:P1] 10+A=1 | [B5T5:5th] +5(5) -> P=6 | [B5T5:6th] B=5 draws (+9->4) | [B5T5:Split] 3B/6P/1T | [B5T5:Cards] 6c (P) |
| [B5T5:P2] 8+4=2 | [B5T5:5th] +5(5) -> P=7 | [B5T5:6th] B=5 draws (+9->4) | [B5T5:Split] 2B/7P/1T | [B5T5:Cards] 6c (P) |
| [B5T5:P3] 10+3=3 | [B5T5:5th] +5(5) -> P=8 | [B5T5:6th] B=5 draws (+9->4) | [B5T5:Split] 1B/8P/1T | [B5T5:Cards] 6c (P) |
| [B5T5:P4] A+3=4 | [B5T5:5th] +5(5) -> P=9 | [B5T5:6th] B=5 draws (+9->4) | [B5T5:Split] 0B/9P/1T | [B5T5:Cards] 6c (P) |
| [B5T5:P5] 2+3=5 | [B5T5:5th] +5(5) -> P=0 | [B5T5:6th] B=5 draws (+9->4) | [B5T5:Split] 9B/0P/1T | [B5T5:Cards] 6c (B) |
In 6-card cell [B5T5], Banker 5 (2+3) can reach a 3-card 7 (Dragon 7) by drawing rank 2 or a 3-card 6 (Super 6) by drawing rank 1 after Player's 5.
Once [B5T5] resolves (19B/35P/6T across 60 branches), the winning side logs to the Big Road on shoe BBPPPBBBBP.
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About 64 minutes of lessons covering outcomes, the Bead Plate, Big Road columns, and dragon tails.
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