In cell B4T4, a Banker holding two-card total 4 (2+2) faces a Player fifth card valued at 4 (4). Under BANKER_TABLEAU[4][4], the Banker DRAWS, resolving in 6 cards with a 15B / 39P / 6T split across the 60 (P0..P5 × 6th-card 0..9) branches.
Verified scoreboard paired with tableau cell B4T4 (Banker 4 vs Player 3rd card 4).
Column 2 has 3 beads. Column 1 has 3 beads. Same depth → red (=).
Common table reading watchout: Comparing the wrong columns. Compare Column 2, the one that just finished, with Column 1.
This bead is at Row 4. Column 1 stopped at Row 3, one row above → blue (≠).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 1 stopped exactly one row above this bead.
This bead is at Row 2. Column 2 has a bead at Row 2 too → red (=).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 2 stopped exactly one row above this bead.
Verified via bankerShouldDraw(4, 4) === true on pair 2+2.
Exact resolution across 6 legal Player starts (0–5) × 10 sixth-card values (0–9).
Three-card Player totals produced when fifth card 4 (4) lands on P0..P5.
How standing Banker 4 fares against the 6 Player 3-card totals for P3=4.
Sample sixth card 9 (9) verified through resolveHand().
Under [B4T4], Banker holds two-card total 4 (2+2) while Player draws fifth-card 4 (point value 4) onto an initial 0–5 total. Across those six legal Player starts, [B4T4] produces three-card Player totals of P0+4->4, P1+4->5, P2+4->6, P3+4->7, P4+4->8, P5+4->9.
Because [B4T4] sits inside the active draw window for Banker 4, the dealer deals a sixth card to 2+2: across all 60 (P0..P5 × sixth-card 0..9) combinations in [B4T4], Banker captures 15 wins, Player captures 39 wins, and 6 branches tie.
| B4T4 Player Start | B4T4 5th Card | B4T4 Banker 4 Action | B4T4 10-Card Split | B4T4 Sample Result |
|---|---|---|---|---|
| [B4T4:P0] 10+K=0 | [B4T4:5th] +4(4) -> P=4 | [B4T4:6th] B=4 draws (+9->3) | [B4T4:Split] 5B/4P/1T | [B4T4:Cards] 6c (P) |
| [B4T4:P1] 7+4=1 | [B4T4:5th] +4(4) -> P=5 | [B4T4:6th] B=4 draws (+9->3) | [B4T4:Split] 4B/5P/1T | [B4T4:Cards] 6c (P) |
| [B4T4:P2] 10+2=2 | [B4T4:5th] +4(4) -> P=6 | [B4T4:6th] B=4 draws (+9->3) | [B4T4:Split] 3B/6P/1T | [B4T4:Cards] 6c (P) |
| [B4T4:P3] 9+4=3 | [B4T4:5th] +4(4) -> P=7 | [B4T4:6th] B=4 draws (+9->3) | [B4T4:Split] 2B/7P/1T | [B4T4:Cards] 6c (P) |
| [B4T4:P4] 2+2=4 | [B4T4:5th] +4(4) -> P=8 | [B4T4:6th] B=4 draws (+9->3) | [B4T4:Split] 1B/8P/1T | [B4T4:Cards] 6c (P) |
| [B4T4:P5] A+4=5 | [B4T4:5th] +4(4) -> P=9 | [B4T4:6th] B=4 draws (+9->3) | [B4T4:Split] 0B/9P/1T | [B4T4:Cards] 6c (P) |
In 6-card cell [B4T4], Banker 4 (2+2) can reach a 3-card 7 (Dragon 7) by drawing rank 3 or a 3-card 6 (Super 6) by drawing rank 2 after Player's 4.
Once [B4T4] resolves (15B/39P/6T across 60 branches), the winning side logs to the Big Road on shoe BBBPPPBBBB.
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About 64 minutes of lessons covering outcomes, the Bead Plate, Big Road columns, and dragon tails.
Train Third-Card Rule decisions, depth counting, lookback column references, and derived-road speed recognition.
Visual step-by-step breakdowns with closed captions, chapter markers, and full searchable transcripts.
Macau Cantonese, French, and mathematical table terms explained in plain English with road diagrams.
Direct answers to real student questions on dragon tails, tie handling, lookback rules, and table variants.
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