In cell B3T7, a Banker holding two-card total 3 (10+3) faces a Player fifth card valued at 7 (7). Under BANKER_TABLEAU[3][7], the Banker DRAWS, resolving in 6 cards with a 27B / 27P / 6T split across the 60 (P0..P5 × 6th-card 0..9) branches.
Verified scoreboard paired with tableau cell B3T7 (Banker 3 vs Player 3rd card 7).
This bead is at Row 4. Column 1 stopped at Row 2, more than one row above → red (=).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 1 stopped exactly one row above this bead.
This bead is at Row 2. Column 2 has a bead at Row 2 too → red (=).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 2 stopped exactly one row above this bead.
Column 5 has 1 bead. Column 2 has 4 beads. Different depth → blue (≠).
Common table reading watchout: Comparing the wrong columns. Compare Column 5, the one that just finished, with Column 2.
Verified via bankerShouldDraw(3, 7) === true on pair 10+3.
Exact resolution across 6 legal Player starts (0–5) × 10 sixth-card values (0–9).
Three-card Player totals produced when fifth card 7 (7) lands on P0..P5.
How standing Banker 3 fares against the 6 Player 3-card totals for P3=7.
Sample sixth card 3 (3) verified through resolveHand().
Under [B3T7], Banker holds two-card total 3 (10+3) while Player draws fifth-card 7 (point value 7) onto an initial 0–5 total. Across those six legal Player starts, [B3T7] produces three-card Player totals of P0+7->7, P1+7->8, P2+7->9, P3+7->0, P4+7->1, P5+7->2.
Because [B3T7] sits inside the active draw window for Banker 3, the dealer deals a sixth card to 10+3: across all 60 (P0..P5 × sixth-card 0..9) combinations in [B3T7], Banker captures 27 wins, Player captures 27 wins, and 6 branches tie.
| B3T7 Player Start | B3T7 5th Card | B3T7 Banker 3 Action | B3T7 10-Card Split | B3T7 Sample Result |
|---|---|---|---|---|
| [B3T7:P0] 6+4=0 | [B3T7:5th] +7(7) -> P=7 | [B3T7:6th] B=3 draws (+3->6) | [B3T7:Split] 2B/7P/1T | [B3T7:Cards] 6c (P) |
| [B3T7:P1] 10+A=1 | [B3T7:5th] +7(7) -> P=8 | [B3T7:6th] B=3 draws (+3->6) | [B3T7:Split] 1B/8P/1T | [B3T7:Cards] 6c (P) |
| [B3T7:P2] 8+4=2 | [B3T7:5th] +7(7) -> P=9 | [B3T7:6th] B=3 draws (+3->6) | [B3T7:Split] 0B/9P/1T | [B3T7:Cards] 6c (P) |
| [B3T7:P3] 10+3=3 | [B3T7:5th] +7(7) -> P=0 | [B3T7:6th] B=3 draws (+3->6) | [B3T7:Split] 9B/0P/1T | [B3T7:Cards] 6c (B) |
| [B3T7:P4] A+3=4 | [B3T7:5th] +7(7) -> P=1 | [B3T7:6th] B=3 draws (+3->6) | [B3T7:Split] 8B/1P/1T | [B3T7:Cards] 6c (B) |
| [B3T7:P5] 2+3=5 | [B3T7:5th] +7(7) -> P=2 | [B3T7:6th] B=3 draws (+3->6) | [B3T7:Split] 7B/2P/1T | [B3T7:Cards] 6c (B) |
In 6-card cell [B3T7], Banker 3 (10+3) can reach a 3-card 7 (Dragon 7) by drawing rank 4 or a 3-card 6 (Super 6) by drawing rank 3 after Player's 7.
Once [B3T7] resolves (27B/27P/6T across 60 branches), the winning side logs to the Big Road on shoe PPBBBBPPBB.
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