In cell B2T7, a Banker holding two-card total 2 (8+4) faces a Player fifth card valued at 7 (7). Under BANKER_TABLEAU[2][7], the Banker DRAWS, resolving in 6 cards with a 27B / 27P / 6T split across the 60 (P0..P5 × 6th-card 0..9) branches.
Verified scoreboard paired with tableau cell B2T7 (Banker 2 vs Player 3rd card 7).
This bead is at Row 3. Column 2 stopped at Row 1, more than one row above → red (=).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 2 stopped exactly one row above this bead.
This bead is at Row 4. Column 1 stopped at Row 2, more than one row above → red (=).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 1 stopped exactly one row above this bead.
Column 5 has 1 bead. Column 2 has 1 bead. Same depth → red (=).
Common table reading watchout: Comparing the wrong columns. Compare Column 5, the one that just finished, with Column 2.
Verified via bankerShouldDraw(2, 7) === true on pair 8+4.
Exact resolution across 6 legal Player starts (0–5) × 10 sixth-card values (0–9).
Three-card Player totals produced when fifth card 7 (7) lands on P0..P5.
How standing Banker 2 fares against the 6 Player 3-card totals for P3=7.
Sample sixth card 4 (4) verified through resolveHand().
Under [B2T7], Banker holds two-card total 2 (8+4) while Player draws fifth-card 7 (point value 7) onto an initial 0–5 total. Across those six legal Player starts, [B2T7] produces three-card Player totals of P0+7->7, P1+7->8, P2+7->9, P3+7->0, P4+7->1, P5+7->2.
Because [B2T7] sits inside the active draw window for Banker 2, the dealer deals a sixth card to 8+4: across all 60 (P0..P5 × sixth-card 0..9) combinations in [B2T7], Banker captures 27 wins, Player captures 27 wins, and 6 branches tie.
| B2T7 Player Start | B2T7 5th Card | B2T7 Banker 2 Action | B2T7 10-Card Split | B2T7 Sample Result |
|---|---|---|---|---|
| [B2T7:P0] 10+K=0 | [B2T7:5th] +7(7) -> P=7 | [B2T7:6th] B=2 draws (+4->6) | [B2T7:Split] 2B/7P/1T | [B2T7:Cards] 6c (P) |
| [B2T7:P1] 7+4=1 | [B2T7:5th] +7(7) -> P=8 | [B2T7:6th] B=2 draws (+4->6) | [B2T7:Split] 1B/8P/1T | [B2T7:Cards] 6c (P) |
| [B2T7:P2] 10+2=2 | [B2T7:5th] +7(7) -> P=9 | [B2T7:6th] B=2 draws (+4->6) | [B2T7:Split] 0B/9P/1T | [B2T7:Cards] 6c (P) |
| [B2T7:P3] 9+4=3 | [B2T7:5th] +7(7) -> P=0 | [B2T7:6th] B=2 draws (+4->6) | [B2T7:Split] 9B/0P/1T | [B2T7:Cards] 6c (B) |
| [B2T7:P4] 2+2=4 | [B2T7:5th] +7(7) -> P=1 | [B2T7:6th] B=2 draws (+4->6) | [B2T7:Split] 8B/1P/1T | [B2T7:Cards] 6c (B) |
| [B2T7:P5] A+4=5 | [B2T7:5th] +7(7) -> P=2 | [B2T7:6th] B=2 draws (+4->6) | [B2T7:Split] 7B/2P/1T | [B2T7:Cards] 6c (B) |
In 6-card cell [B2T7], Banker 2 (8+4) can reach a 3-card 7 (Dragon 7) by drawing rank 5 or a 3-card 6 (Super 6) by drawing rank 4 after Player's 7.
Once [B2T7] resolves (27B/27P/6T across 60 branches), the winning side logs to the Big Road on shoe BBPBBBBPPB.
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