In cell B1T1, a Banker holding two-card total 1 (10+A) faces a Player fifth card valued at 1 (A). Under BANKER_TABLEAU[1][1], the Banker DRAWS, resolving in 6 cards with a 33B / 21P / 6T split across the 60 (P0..P5 × 6th-card 0..9) branches.
Verified scoreboard paired with tableau cell B1T1 (Banker 1 vs Player 3rd card 1).
This bead is at Row 4. Column 1 stopped at Row 2, more than one row above → red (=).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 1 stopped exactly one row above this bead.
This bead is at Row 2. Column 2 has a bead at Row 2 too → red (=).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 2 stopped exactly one row above this bead.
Column 5 has 1 bead. Column 2 has 4 beads. Different depth → blue (≠).
Common table reading watchout: Comparing the wrong columns. Compare Column 5, the one that just finished, with Column 2.
Verified via bankerShouldDraw(1, 1) === true on pair 10+A.
Exact resolution across 6 legal Player starts (0–5) × 10 sixth-card values (0–9).
Three-card Player totals produced when fifth card A (1) lands on P0..P5.
How standing Banker 1 fares against the 6 Player 3-card totals for P3=1.
Sample sixth card 9 (9) verified through resolveHand().
Under [B1T1], Banker holds two-card total 1 (10+A) while Player draws fifth-card A (point value 1) onto an initial 0–5 total. Across those six legal Player starts, [B1T1] produces three-card Player totals of P0+1->1, P1+1->2, P2+1->3, P3+1->4, P4+1->5, P5+1->6.
Because [B1T1] sits inside the active draw window for Banker 1, the dealer deals a sixth card to 10+A: across all 60 (P0..P5 × sixth-card 0..9) combinations in [B1T1], Banker captures 33 wins, Player captures 21 wins, and 6 branches tie.
| B1T1 Player Start | B1T1 5th Card | B1T1 Banker 1 Action | B1T1 10-Card Split | B1T1 Sample Result |
|---|---|---|---|---|
| [B1T1:P0] 6+4=0 | [B1T1:5th] +A(1) -> P=1 | [B1T1:6th] B=1 draws (+9->0) | [B1T1:Split] 8B/1P/1T | [B1T1:Cards] 6c (P) |
| [B1T1:P1] 10+A=1 | [B1T1:5th] +A(1) -> P=2 | [B1T1:6th] B=1 draws (+9->0) | [B1T1:Split] 7B/2P/1T | [B1T1:Cards] 6c (P) |
| [B1T1:P2] 8+4=2 | [B1T1:5th] +A(1) -> P=3 | [B1T1:6th] B=1 draws (+9->0) | [B1T1:Split] 6B/3P/1T | [B1T1:Cards] 6c (P) |
| [B1T1:P3] 10+3=3 | [B1T1:5th] +A(1) -> P=4 | [B1T1:6th] B=1 draws (+9->0) | [B1T1:Split] 5B/4P/1T | [B1T1:Cards] 6c (P) |
| [B1T1:P4] A+3=4 | [B1T1:5th] +A(1) -> P=5 | [B1T1:6th] B=1 draws (+9->0) | [B1T1:Split] 4B/5P/1T | [B1T1:Cards] 6c (P) |
| [B1T1:P5] 2+3=5 | [B1T1:5th] +A(1) -> P=6 | [B1T1:6th] B=1 draws (+9->0) | [B1T1:Split] 3B/6P/1T | [B1T1:Cards] 6c (P) |
In 6-card cell [B1T1], Banker 1 (10+A) can reach a 3-card 7 (Dragon 7) by drawing rank 6 or a 3-card 6 (Super 6) by drawing rank 5 after Player's A.
Once [B1T1] resolves (33B/21P/6T across 60 branches), the winning side logs to the Big Road on shoe PPBBBBPPBB.
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