In cell B0T9, a Banker holding two-card total 0 (6+4) faces a Player fifth card valued at 9 (9). Under BANKER_TABLEAU[0][9], the Banker DRAWS, resolving in 6 cards with a 35B / 19P / 6T split across the 60 (P0..P5 × 6th-card 0..9) branches.
Verified scoreboard paired with tableau cell B0T9 (Banker 0 vs Player 3rd card 9).
Column 2 has 3 beads. Column 1 has 2 beads. Different depth → blue (≠).
Common table reading watchout: Comparing the wrong columns. Compare Column 2, the one that just finished, with Column 1.
This bead is at Row 4. Column 1 stopped at Row 2, more than one row above → red (=).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 1 stopped exactly one row above this bead.
Column 6 has 1 bead. Column 3 has 4 beads. Different depth → blue (≠).
Common table reading watchout: Comparing the wrong columns. Compare Column 6, the one that just finished, with Column 3.
Verified via bankerShouldDraw(0, 9) === true on pair 6+4.
Exact resolution across 6 legal Player starts (0–5) × 10 sixth-card values (0–9).
Three-card Player totals produced when fifth card 9 (9) lands on P0..P5.
How standing Banker 0 fares against the 6 Player 3-card totals for P3=9.
Sample sixth card 8 (8) verified through resolveHand().
Under [B0T9], Banker holds two-card total 0 (6+4) while Player draws fifth-card 9 (point value 9) onto an initial 0–5 total. Across those six legal Player starts, [B0T9] produces three-card Player totals of P0+9->9, P1+9->0, P2+9->1, P3+9->2, P4+9->3, P5+9->4.
Because [B0T9] sits inside the active draw window for Banker 0, the dealer deals a sixth card to 6+4: across all 60 (P0..P5 × sixth-card 0..9) combinations in [B0T9], Banker captures 35 wins, Player captures 19 wins, and 6 branches tie.
| B0T9 Player Start | B0T9 5th Card | B0T9 Banker 0 Action | B0T9 10-Card Split | B0T9 Sample Result |
|---|---|---|---|---|
| [B0T9:P0] 10+K=0 | [B0T9:5th] +9(9) -> P=9 | [B0T9:6th] B=0 draws (+8->8) | [B0T9:Split] 0B/9P/1T | [B0T9:Cards] 6c (P) |
| [B0T9:P1] 7+4=1 | [B0T9:5th] +9(9) -> P=0 | [B0T9:6th] B=0 draws (+8->8) | [B0T9:Split] 9B/0P/1T | [B0T9:Cards] 6c (B) |
| [B0T9:P2] 10+2=2 | [B0T9:5th] +9(9) -> P=1 | [B0T9:6th] B=0 draws (+8->8) | [B0T9:Split] 8B/1P/1T | [B0T9:Cards] 6c (B) |
| [B0T9:P3] 9+4=3 | [B0T9:5th] +9(9) -> P=2 | [B0T9:6th] B=0 draws (+8->8) | [B0T9:Split] 7B/2P/1T | [B0T9:Cards] 6c (B) |
| [B0T9:P4] 2+2=4 | [B0T9:5th] +9(9) -> P=3 | [B0T9:6th] B=0 draws (+8->8) | [B0T9:Split] 6B/3P/1T | [B0T9:Cards] 6c (B) |
| [B0T9:P5] A+4=5 | [B0T9:5th] +9(9) -> P=4 | [B0T9:6th] B=0 draws (+8->8) | [B0T9:Split] 5B/4P/1T | [B0T9:Cards] 6c (B) |
In 6-card cell [B0T9], Banker 0 (6+4) can reach a 3-card 7 (Dragon 7) by drawing rank 7 or a 3-card 6 (Super 6) by drawing rank 6 after Player's 9.
Once [B0T9] resolves (35B/19P/6T across 60 branches), the winning side logs to the Big Road on shoe BBPPPBBBBP.
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