In cell B0T8, a Banker holding two-card total 0 (10+K) faces a Player fifth card valued at 8 (8). Under BANKER_TABLEAU[0][8], the Banker DRAWS, resolving in 6 cards with a 31B / 23P / 6T split across the 60 (P0..P5 × 6th-card 0..9) branches.
Verified scoreboard paired with tableau cell B0T8 (Banker 0 vs Player 3rd card 8).
Column 4 has 1 bead. Column 3 has 1 bead. Same depth → red (=).
Common table reading watchout: Comparing the wrong columns. Compare Column 4, the one that just finished, with Column 3.
Column 5 has 1 bead. Column 3 has 1 bead. Same depth → red (=).
Common table reading watchout: Comparing the wrong columns. Compare Column 5, the one that just finished, with Column 3.
This bead is at Row 2. Column 3 stopped at Row 1, one row above → blue (≠).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 3 stopped exactly one row above this bead.
Verified via bankerShouldDraw(0, 8) === true on pair 10+K.
Exact resolution across 6 legal Player starts (0–5) × 10 sixth-card values (0–9).
Three-card Player totals produced when fifth card 8 (8) lands on P0..P5.
How standing Banker 0 fares against the 6 Player 3-card totals for P3=8.
Sample sixth card 7 (7) verified through resolveHand().
Under [B0T8], Banker holds two-card total 0 (10+K) while Player draws fifth-card 8 (point value 8) onto an initial 0–5 total. Across those six legal Player starts, [B0T8] produces three-card Player totals of P0+8->8, P1+8->9, P2+8->0, P3+8->1, P4+8->2, P5+8->3.
Because [B0T8] sits inside the active draw window for Banker 0, the dealer deals a sixth card to 10+K: across all 60 (P0..P5 × sixth-card 0..9) combinations in [B0T8], Banker captures 31 wins, Player captures 23 wins, and 6 branches tie.
| B0T8 Player Start | B0T8 5th Card | B0T8 Banker 0 Action | B0T8 10-Card Split | B0T8 Sample Result |
|---|---|---|---|---|
| [B0T8:P0] 10+K=0 | [B0T8:5th] +8(8) -> P=8 | [B0T8:6th] B=0 draws (+7->7) | [B0T8:Split] 1B/8P/1T | [B0T8:Cards] 6c (P) |
| [B0T8:P1] 7+4=1 | [B0T8:5th] +8(8) -> P=9 | [B0T8:6th] B=0 draws (+7->7) | [B0T8:Split] 0B/9P/1T | [B0T8:Cards] 6c (P) |
| [B0T8:P2] 10+2=2 | [B0T8:5th] +8(8) -> P=0 | [B0T8:6th] B=0 draws (+7->7) | [B0T8:Split] 9B/0P/1T | [B0T8:Cards] 6c (B) |
| [B0T8:P3] 9+4=3 | [B0T8:5th] +8(8) -> P=1 | [B0T8:6th] B=0 draws (+7->7) | [B0T8:Split] 8B/1P/1T | [B0T8:Cards] 6c (B) |
| [B0T8:P4] 2+2=4 | [B0T8:5th] +8(8) -> P=2 | [B0T8:6th] B=0 draws (+7->7) | [B0T8:Split] 7B/2P/1T | [B0T8:Cards] 6c (B) |
| [B0T8:P5] A+4=5 | [B0T8:5th] +8(8) -> P=3 | [B0T8:6th] B=0 draws (+7->7) | [B0T8:Split] 6B/3P/1T | [B0T8:Cards] 6c (B) |
In 6-card cell [B0T8], Banker 0 (10+K) can reach a 3-card 7 (Dragon 7) by drawing rank 7 or a 3-card 6 (Super 6) by drawing rank 6 after Player's 8.
Once [B0T8] resolves (31B/23P/6T across 60 branches), the winning side logs to the Big Road on shoe BBBBPBPBPP.
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