In cell B0T6, a Banker holding two-card total 0 (10+K) faces a Player fifth card valued at 6 (6). Under BANKER_TABLEAU[0][6], the Banker DRAWS, resolving in 6 cards with a 23B / 31P / 6T split across the 60 (P0..P5 × 6th-card 0..9) branches.
Verified scoreboard paired with tableau cell B0T6 (Banker 0 vs Player 3rd card 6).
This bead is at Row 2. Column 2 has a bead at Row 2 too → red (=).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 2 stopped exactly one row above this bead.
This bead is at Row 4. Column 1 stopped at Row 1, more than one row above → red (=).
Common table reading watchout: Thinking "no bead at this row" means blue. It is blue only when Column 1 stopped exactly one row above this bead.
Column 6 has 1 bead. Column 3 has 4 beads. Different depth → blue (≠).
Common table reading watchout: Comparing the wrong columns. Compare Column 6, the one that just finished, with Column 3.
Verified via bankerShouldDraw(0, 6) === true on pair 10+K.
Exact resolution across 6 legal Player starts (0–5) × 10 sixth-card values (0–9).
Three-card Player totals produced when fifth card 6 (6) lands on P0..P5.
How standing Banker 0 fares against the 6 Player 3-card totals for P3=6.
Sample sixth card 5 (5) verified through resolveHand().
Under [B0T6], Banker holds two-card total 0 (10+K) while Player draws fifth-card 6 (point value 6) onto an initial 0–5 total. Across those six legal Player starts, [B0T6] produces three-card Player totals of P0+6->6, P1+6->7, P2+6->8, P3+6->9, P4+6->0, P5+6->1.
Because [B0T6] sits inside the active draw window for Banker 0, the dealer deals a sixth card to 10+K: across all 60 (P0..P5 × sixth-card 0..9) combinations in [B0T6], Banker captures 23 wins, Player captures 31 wins, and 6 branches tie.
| B0T6 Player Start | B0T6 5th Card | B0T6 Banker 0 Action | B0T6 10-Card Split | B0T6 Sample Result |
|---|---|---|---|---|
| [B0T6:P0] 10+K=0 | [B0T6:5th] +6(6) -> P=6 | [B0T6:6th] B=0 draws (+5->5) | [B0T6:Split] 3B/6P/1T | [B0T6:Cards] 6c (P) |
| [B0T6:P1] 7+4=1 | [B0T6:5th] +6(6) -> P=7 | [B0T6:6th] B=0 draws (+5->5) | [B0T6:Split] 2B/7P/1T | [B0T6:Cards] 6c (P) |
| [B0T6:P2] 10+2=2 | [B0T6:5th] +6(6) -> P=8 | [B0T6:6th] B=0 draws (+5->5) | [B0T6:Split] 1B/8P/1T | [B0T6:Cards] 6c (P) |
| [B0T6:P3] 9+4=3 | [B0T6:5th] +6(6) -> P=9 | [B0T6:6th] B=0 draws (+5->5) | [B0T6:Split] 0B/9P/1T | [B0T6:Cards] 6c (P) |
| [B0T6:P4] 2+2=4 | [B0T6:5th] +6(6) -> P=0 | [B0T6:6th] B=0 draws (+5->5) | [B0T6:Split] 9B/0P/1T | [B0T6:Cards] 6c (B) |
| [B0T6:P5] A+4=5 | [B0T6:5th] +6(6) -> P=1 | [B0T6:6th] B=0 draws (+5->5) | [B0T6:Split] 8B/1P/1T | [B0T6:Cards] 6c (B) |
In 6-card cell [B0T6], Banker 0 (10+K) can reach a 3-card 7 (Dragon 7) by drawing rank 7 or a 3-card 6 (Super 6) by drawing rank 6 after Player's 6.
Once [B0T6] resolves (23B/31P/6T across 60 branches), the winning side logs to the Big Road on shoe BPPBBBBPBP.
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